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Formula For Determining The Day of the Week |
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Formula | Example 1 | Example 2 | |||
25 Dec. 1848 | 19 Oct. 1781 |
Step 1. | Begin with the last 2 digits of the year. |
48 | 81 |
Step 2. | Add ¼ of this number, desregarding any remainder. | 12 | 20 |
Step 3. | Add the date in the month. | 25 | 19 |
Step 4. | Add according to the month: |
January | 1 (for leap year, 0) | |||||
February | 4 (for leap year, 3) | |||||
March or November | 4 | |||||
April or July | 0 | |||||
May | 2 | |||||
June | 5 | |||||
Auust | 3 | |||||
September or December | 6 | 6 | ||||
October | 1 | 1 | ||||
Stept 5. | Add for the 18th century | 4 | 4 | |||
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19th century | 2 | 2 | |||
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20th century | 0 | ||||
21st century | 6 | _____ | _____ | |||
Step 6. | Total the numbers. | 93 | 125 | |||
Stept 7. | Divide by 7. Check the remainder against the chart to determine the day of the week. | 13 with a remainder of 2. | 17 with a remainder of 6. | |||
1= Sunday | 5= Thursday | Christmas was on Monday. | Cornwallis surrendered at Yorktown on Friday. | |||
2= Monday | 6= Friday | |||||
3= Tuesday | 0= Saturday | |||||
4= Wednesday |
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