Puzzles Archive
This is a list of the previous puzzles that have been sent out by
E-mail.
Don't forget to signup for "The MindBender" here.
To see the answer, click and hold your mouse button just to the right
of the red arrow 
and drag down. This will highlight
the answer and make it visible.
February 5, 2001
MindBender
Aunt Mary's Pie
Aunt Mary made her famous apple pie. However, just before dinner,
someone stole it from her front window sill where it was cooling,
never to be seen again. There were four suspects, including Aunt
Mary herself. Each made a statement, but only one spoke the truth.
Their statements are below. Who stole Aunt Mary's pie?
Uncle Tom: I did it.
Uncle John: Either Tom or I did it.
Uncle Bill: Aunt Mary did it.
Aunt Mary: John did it.
___________________________
Mini-MindBender for Kids
Letter Sequence
What letter would logically replace the question mark below?
AGBFCEDDECF?GA
___________________________
...Answer to MindBender
Aunt Mary's Pie
If Uncle Tom did it, both Uncle Tom's and Uncle John's statements are
true - so Uncle Tom is innocent. If Uncle John did it, both Uncle
John's and Aunt Mary's statements are true - so Uncle John is
innocent. If Uncle Bill did it, no statement is true - so Uncle Bill
is innocent. Therefore, Aunt Mary did it and only Uncle Bill's
statement is true. Aunt Mary stole her own pie! I guess she just
didn't want to share.
This MindBender was modified from a puzzle in Norman D. Willis'
"The Little Giant Encyclopedia of Logic Puzzles."
___________________________
Answer to Mini-MindBender for Kids
Letter Sequence
B. Every other letter is in alphabetical order, left to right for odd
numbered letters, and right to left for even numbered letters.
This MindBender was modified from a puzzle in Dr. Abbie F. Salny's
"The Mensa 365 Brain Puzzlers Calendar" for 2001.
February 12, 2001
MindBender
Mowing
I can mow the lawn in two hours. My daughter can mow the lawn in
three hours. If we use two mowers and both work together, how
long will it take us to mow the lawn?
___________________________
Mini-MindBender for Kids
Subtraction
In the following subtraction, A, B, and C are 0, 4, and 8 in some
order. What is the subtraction problem using digits and not letters?
ACA
-CCC
_____
CBC
___________________________
...Answer to MindBender
Mowing
In one hour I can mow 1/2 of the lawn. In one hour my daughter
can mow 1/3 of the lawn. Together in one hour, we can mow
1/2 + 1/3 or 5/6 of the lawn. So together it will take us 6/5
hours, or one hour and 12 minutes, to mow the lawn.
This MindBender was modified from a puzzle in Jerry Stickels'
"Mindbending Puzzles" calendar for 2000.
___________________________
Answer to Mini-MindBender for Kids
Subtraction
From the tens column, B must be 0. Therefore, from the ones or
hundreds column, A must be 8 and C must be 4.
848
-444
_____
404
This MindBender was modified from a puzzle in Norman D. Willis'
"The Little Giant Encyclopedia of Logic Puzzles."
February 19, 2001
MindBender
Six Digits
Solve the following sum where the letters are replaced by 0, 1, 3, 5, 7, and 9 in some order:
BCEC
+ECEF
______
AEEAD
___________________________
Mini-MindBender for Kids
Word Change
Change one letter at each step to change FAIl to SOUR in four steps:
FAIL
----
----
----
SOUR
I know of two answers. There may be more.
___________________________
...Answer to MindBender
Six Digits
From the first digit of the sum, A must be 1. Therefore, from
the tens column, E must be 5 and the tens column produces a
carry and the units column must also. From the hundreds column,
C must be 7. Hence B must be 9 from the thousands column. Then,
from the units column, D must be 0 and F must be 3.
9757
+5753
______
15510
This MindBender was modified from a puzzle in Norman D. Willis'
"The Little Giant Encyclopedia of Logic Puzzles."
___________________________
Answer to Mini-MindBender for Kids
Word Change
Two possible answers:
FAIL FAIL
FOIL SAIL
FOUL SOIL
FOUR SOUL
SOUR SOUR
This MindBender was modified from a puzzle in Jerry Stickels'
"Mindbending Puzzles" calendar for 2001.
February 26, 2001
MindBender
Golf Sign
A golfer plays a course he has never played before. At the end of
the first hole there are two paths, each with a sign by them. The
first path sign says, “This is the path to the second tee.” The
second path sign says, “These signs are both true.” In small print
the scorecard says that at least one of the signs is false. Which
path should the golfer take to reach the second tee?
___________________________
Mini-MindBender for Kids
3 Unknowns
What is the value of C in the following set of equations?
A+B=2
C*A+B=5
C*B+A=7
___________________________
...Answer to MindBender
Golf Sign
If the first path is the correct path to the second tee, then both
signs are true, which is not allowed. Therefore, the second path is
the path to the second tee and both statements are false.
This MindBender was modified from a puzzle in Norman D. Willis'
"The Little Giant Encyclopedia of Logic Puzzles."
___________________________
Answer to Mini-MindBender for Kids
3 Unknowns
Adding the left and right sides of the last two equations results in:
C*A+B+C*B+A=12 or
C*(A+B)+(A+B)=12
Then use the first equation to get
C*2+2=12 or C*2=10 or C=5
This MindBender was modified from a puzzle in Jerry Stickels'
"Mindbending Puzzles" calendar for 2000.
March 5, 2001
MindBender
License Plates
The license plates for my state all have three letters, a space,
and three digits (0-9). Assuming that all possible plates are made,
what is the likelihood that any plate will have at least one repeated
letter and/or digit?
___________________________
Mini-MindBender for Kids
Mystery Word
From the following five clues, determine the five letter mystery word.
My first is in PAINT but not in INK.
My second in GREEN but not in DRINK.
My third in TOP and also TOE.
My fourth in GRACE but not in ROW.
My last in LACE and also LINED.
In each bouquet, this word you'll find.
_ _ _ _ _
___________________________
...Answer to MindBender
License Plates
There are 26*26*26*10*10*10 possible license plates. Of these,
26*25*24*10*9*8 or 63.9% have no repeated letter or digit.
Therefore, 36.1% of the plates have at least one repeated letter
or digit.
The MindBender moderator is the source for this MindBender.
___________________________
Answer to Mini-MindBender for Kids
Mystery Word
PETAL
This MindBender was modified from a puzzle in Dr. Abbie F. Salny's
"The Mensa 365 Brain Puzzlers Calendar" for 2001.
March 12, 2001
MindBender
Losing Time
Your clock was correct last midnight and, at that very moment
began to lose 16.5 minutes every hour. When you look at the clock,
it is showing 7:15 in the morning, and it has stopped. In fact, it
stopped two hours ago. What is the correct time now?
___________________________
Mini-MindBender for Kids
Jelly Beans
In a contest to guess how many jelly beans were in a jar, Megan
guessed 23, Emily guessed 15, Alex guessed 20, Max guessed 21, Jake
guessed 17, Billy guessed 19, and Sam guessed 18. Two were off by 4,
two were off by 2, two were off by 1, and one was correct. Who made
the correct guess?
___________________________
...Answer to MindBender
Losing Time
It is noon. The clock shows 435 minutes after midnight (7*60+15).
Since it records only 43.5 (60-16.5) minutes every hour, it had
been running for 435/43.5 or 10 hours when it stopped. It stopped
10 hours after midnight or at 10:00 AM and that was two hours ago.
Therefore, it is now noon.
This MindBender was modified from a puzzle in Victor Serebriakoff's
book, "The Mammoth Book of Astounding Puzzles."
___________________________
Answer to Mini-MindBender for Kids
Jelly Beans
Billy's guess of 19 is correct. Try each of the seven guesses as
the correct answer and see how much off the other answers are. For
example, if 20 were the right answer, the guesses would be off by
3, 5, 0, 1, 3, 1, and 2. This doesn't match the puzzle statement.
The only one of the seven guesses that matches the puzzle statement
when you assume it is correct is 19. So, Billy made the correct guess.
This MindBender was modified from a puzzle in Dr. Abbie F. Salny's
"The Mensa 365 Brain Puzzlers Calendar" for 2001.
March 19, 2001
MindBender
Gaining Time
You took your clock that was losing time (from last week's
MindBender) to a clock repair shop. However, the clock repair shop
was staffed by amateurs. Now it is gaining time! Your clock was
correct when you started it last night at midnight and, at that
very moment, began to gain 18 minutes every hour. When you look at
the clock in the morning, you see it stop. Exactly two hours later,
it is still stopped, but now the time is correct. What is the
correct time now?
___________________________
Mini-MindBender for Kids
Greater Sum
Without actually adding them, which of the following sums is greater?
987654321 123456789
087654321 123456780
007654321 123456700
000654321 123456000
000054321 OR 123450000
000004321 123400000
000000321 123000000
000000021 120000000
+000000001 +100000000
__________ __________
___________________________
...Answer to MindBender
Gaining Time
If the clock stops when it is N minutes after midnight, the
following equation is true:
(N/78 + 2)*60=N
since the clock records 78 (60+18) minutes every hour, and two hours
after recording N minutes (or N/78 hours) and stopping, the clock
is correct when showing N minutes. Solving for N results in N=520
minutes, or 8 hours and 40 minutes, or 8:40 AM.
The MindBender moderator is the source for this MindBender.
___________________________
Answer to Mini-MindBender for Kids
Greater Sum
The sums are equal, both are 1,083,676,269. Without adding, each
column (from the left side of each sum) has one 9 or nine 1s, two
8s or eight 2s, ... , nine 1s or one 9. Thus, each column has the
same sum and carry, so the overall sums are identical.
This MindBender was modified from a puzzle in Raymond Blum's book,
"Math Trick, Puzzles & Games."
March 26, 2001
MindBender
A Word
A common English five-letter word has the following true things
that can be said about it:
1. ADULT has two letters in common with it, not at their correct
places.
2. GUSTO has no common letter with it.
3. STORY has one common letter, at the correct place.
4. BUILT has one common letter, at the correct place.
5. DYING has one common letter, not at the correct place.
6. BUGLE has two common letters, but only one at the correct place.
7. LIGHT has no common letter with it.
What is the word?
___________________________
Mini-MindBender for Kids
Two-Digit Subtraction
Pick any two-digit number where the two digits are different. Reverse
the digits to get a second two-digit number. Subtract the smaller
two-digit number from the larger two-digit number. There is something
that is true about the difference, regardless of what you chose as
the original two-digit number. What is that "something special" about
the difference? And, why is this the case?
___________________________
...Answer to MindBender
A Word
Since GUSTO and LIGHT have no good letters, the only good letter in
BUILT is B which begins the desired word. One good letter in BUGLE
is B and the other is E (out of place). The good letters in ADULT
are A and D, so the good letter in DYING is D. This makes Y false.
So, the only good letter in STORY is R, at the correct place. The
desired word now has the form B _ D R _ or B _ _ R D with A and E
in the blanks. This gives us the following possible words: BADRE
(eliminated since the E cannot be last as it is out of place in
BUGLE), BEDRA, BAERD, or BEARD. Therefore, the desired word is BEARD.
This can also be solved without #7:
Applying #2 to the list gives us:
1: ADxLx (2 - diff loc)
3: xxxRY (1 - corr loc)
4: BxILx (1 - corr loc)
5: DYINx (1 - diff loc)
6: BxxLE (2 - 1 corr, 1 not)
Next, L can't be a letter because of conflict between 1 and 4 (it's in the same
position in both words, but it would be in the correct position according to
one, but incorrect according to the other. Can't be both, therefore not
included). Now we have:
1: ADxxx (2 - diff loc)
3: xxxRY (1 - corr loc)
4: BxIxx (1 - corr loc)
5: DYINx (1 - diff loc)
6: BxxxE (2 - 1 corr, 1 not)
Next, we now know that A and D are correct, which means that Y, I, and N (from 5)
are not. That leaves us with:
1: ADxxx (2 - diff loc)
3: xxxRx (1 - corr loc)
4: Bxxxx (1 - corr loc)
5: Dxxxx (1 - diff loc)
6: BxxxE (2 - 1 corr, 1 not)
This gives us a known pattern of: B _ _ R _ (with reamaing letters ADE, and D
can't be in the 2nd position). The rest is as explained above.
This MindBender was modified from a puzzle in Pierre Berloquin's book,
"100 Games of Logic."
___________________________
Answer to Mini-MindBender for Kids
Two-Digit Subtraction
The difference between the two numbers will always be a positive
multiple of 9. The reason for this is as follows:
Assume the first number is AB and the reversed number is BA. Also
assume that A is greater than B. Then, the difference (AB - BA) can
be represented as:
10*A + B - (10*B + A) or
10*A + B -10*B - A or
9*A - 9*B or
9*(A-B) and since A is greater than B, 9*(A-B) is a positive
multiple of 9.
The MindBender moderator's granddaughter, Megan, is the source and
inspiration for this Mini-MindBender.
April 2, 2001
MindBender
A Theft
A theft has occurred and one of three suspects is guilty. The three
suspects are A, B, and C. In an unusual twist, the guilty person's
statement is true and the two innocent persons' statements are false.
The following are the three statements:
A says: B is guilty.
B says: A's statement is true.
C says: A's statement is false.
Who is guilty?
___________________________
Mini-MindBender for Kids
Multiplication Square
Today's Mini-MindBender is not really a problem, but rather a technique
for doing two-digit multiplication. Suppose you want to multiply 47 by
73. Break 47 into 40 and 7 and place the 40 above column one (and the 7
above column two) of a two-by-two square. Break 73 into 70 and 3 and
place the 70 to the left of row one (and the 3 to the left of row two)
of the same two-by-two square. Now do the four simple multiplications
(40*70, 7*70, 40*3, and 7*3) and place the answers into the two-by-two
square. Now add those four answers (2800, 490, 120, and 21) and the
result of that addition is the product of 47 and 73.
| 40 | 7 |
___________________
| | |
70 | 2800 | 490 |
| | |
___________________
| | |
3 | 120 | 21 |
| | |
___________________
Sum of 4 boxes: 3431
___________________________
...Answer to MindBender
A Theft
If A is telling the truth, then B is also telling the truth. But,
there is only one true statement. Therefore, A is not telling the
truth. Likewise, if B is telling the truth, A is telling the truth.
Therefore, B is not telling the truth. But if C is telling the
truth, A's statement is false and B's statement is also false.
Therefore, C is guilty.
This MindBender was modified from a puzzle in Norman D. Willis'
"The Little Giant Encyclopedia of Logic Puzzles."
___________________________
Answer to Mini-MindBender for Kids
Multiplication Square
Use this week's Mini-MindBender to help you learn and understand
two-digit multiplication. Practice it as much as necessary.
The MindBender moderator is the source for this Mini-MindBender.
April 9, 2001
MindBender
Missiles
Two missiles are speeding directly toward each other, one at 9000
miles per hour and the other at 21000 miles per hour. The missiles
are now 6317 miles apart. How far apart are they three minutes before
they collide?
___________________________
Mini-MindBender for Kids
Fruit Prices
A fruit market sells fruit based on an unusual pricing system. A
peach is 8 cents. A banana is 9 cents. A pear is 6 cents. A fig
is 5 cents. Using this system, how much is a pineapple?
___________________________
...Answer to MindBender
Missiles
The two missiles approach each other at 9000+21000 or 30000 miles
per hour. This is 500 miles per minute. So at three minutes before
collision, they are 1500 miles apart.
This MindBender was modified from a puzzle in Martin Gardner's book,
"My Best Mathematical and Logic Puzzles."
___________________________
Answer to Mini-MindBender for Kids
Fruit Prices
14 cents. Consonants in the fruit's name are worth 2 cents. Vowels
in the fruit's name are worth 1 cent.
This MindBender was modified from a puzzle in Dr. Abbie F. Salny's
"The Mensa 365 Brain Puzzlers Calendar" for 2001.
April 16, 2001
MindBender
Trains
It takes a passenger train twice as long to pass a freight train
(after it first overtakes it and when both trains are going the same
direction) as it takes the two trains to pass when going in opposite
directions. How many times faster than the freight train is the
passenger train?
___________________________
Mini-MindBender for Kids
Make A Palindrome
Pick any two-digit number that is NOT a palindrome (a number that
reads the same forward and backward). Reverse the number and add
that reversed number to the first number. Continue reversing the
result and adding until you get a palindrome. For example, 49+94=143;
143+341=484 or a palindrome in two steps. This will work when you
start with any two-digit number that is not a palindrome. Keep your
pencil sharp, work carefully, and determine how many steps it takes
if you start with 89 or 98.
___________________________
...Answer to MindBender
Trains
The passenger train is three times as fast as the freight train.
Let the passenger and freight train rates be P and F respectively.
Then, since the distance for both passes is the same (the sum of the
two train lengths), and since the rates of passing are P-F (same
direction) and P+F (opposite directions), the following holds (where
X is the time for passing when going in the same direction):
Sum of the two train lengths = (P-F)*X = (P+F)*X/2 or 2PX-2FX=PX+FX
or PX=3FX or P=3F.
This MindBender was modified from a puzzle in C. R. Wylie Jr.'s book,
"101 Puzzles in Thought & Logic."
___________________________
Answer to Mini-MindBender for Kids
Make A Palindrome
It takes 24 steps and the resulting palindrome is 8,813,200,023,188.
This MindBender was modified from a puzzle in Raymond Blum's book,
"Mathamusements."
April 23, 2001
MindBender
ABCs
The following matrix is arranged according to a logical principle.
What is that principle?
CABCAB
BABCAC
ACABBA
CBACCB
BACBAC
CBACBA
___________________________
Mini-MindBender for Kids
Ages
14 years ago Suzie was one-third of her dad's age.
Suzie is now one-half of her dad's age.
In 14 years, she will be three-fifths of her dad's age.
It does appear that Suzie is catching up. However, how old are Suzie
and her dad now?
___________________________
...Answer to MindBender
ABCs
Starting from the third row, third character (A) and moving in a
spiral (to the right, down, left, up, right, etc., and ending in the
lower left), ABCABCABC...ABC has been written.
This MindBender was modified from a puzzle in Pierre Berloquin's book,
"100 Games of Logic."
___________________________
Answer to Mini-MindBender for Kids
Ages
Only the first two statements are needed. Let Suzie's age be S and her
dad's age be D. Then, using Algebra, we have:
S - 14 = (D - 14)/3
S = D/2
Substituting S = D/2 into the first equation gives:
D/2 - 14 = (D - 14)/3 or
3D - 84 = 2D - 28 or
D = 56 so
Suzie is 28 and her dad is 56.
The MindBender moderator is the source for this MindBender.
April 30, 2001
MindBender
Double Crossed
Place three Xs in any of the squares in the following matrix to result
in two Xs in each row, each column, and each diagonal:
_________________
| X | | X | |
_________________
| X | | | |
_________________
| | X | | |
_________________
| | | X | |
_________________
___________________________
Mini-MindBender for Kids
Missing Signs
Look at the following equation. It is missing all the mathematical
operation signs. Replace the question marks with operators (not all
the same) to make the equation true.
32 ? 12 ? 4 ? 1 = 97
___________________________
...Answer to MindBender
Double Crossed
Put Os in the matrix where no X can be placed because there are already
two Xs in a row or column. The following is the resulting matrix:
_________________
| X | O | X | O |
_________________
| X | | O | |
_________________
| O | X | O | |
_________________
| O | | X | |
_________________
The only square in the lower-left-to-upper-right diagonal that allows an
X already has one. This means that we must double that square with two Xs.
Doing that and again placing Os as above results in the following matrix:
_________________
| X | O | X | O |
_________________
| X | O | O | |
_________________
| O | XX| O | O |
_________________
| O | O | X | |
_________________
leaving us with only two squares that can take the last two Xs. This gives
us the answer:
_________________
| X | O | X | O |
_________________
| X | O | O | X |
_________________
| O | XX| O | O |
_________________
| O | O | X | X |
_________________
This MindBender was modified from a puzzle in David J. Bodycombe's
book, "The Mammoth Puzzle Carnival."
___________________________
Answer to Mini-MindBender for Kids
Missing Signs
32 times 3 plus 1 equals 97. 12 divided by 4 equals 3. Therefore,
32 X 12 / 4 + 1 = 97
This MindBender was modified from a puzzle in Victor Serebriakoff's
book, "The Mammoth Book of Astounding Puzzles."
May 7, 2001
MindBender
Swimming
Percy and Tommy had a swimming race of 195 yards in a local canal.
Tommy beat Percy by 28 yards. They race again over the same course,
with Tommy starting 32 yards behind Percy (who still swims 195
yards). Assuming they both swim at the same speed as before, who
won this second race?
___________________________
Mini-MindBender for Kids
Candy
A candy store sells large jelly beans and fruit drops. Six jelly beans
and five fruit drops cost 85 cents. Six fruit drops and five jelly
beans cost 80 cents. What are the per piece prices for jelly beans
and fruit drops?
___________________________
...Answer to MindBender
Swimming
In the first race, Tommy swims the 195 yards in one unit of time.
Percy swims 167 yards in the same time and takes 1 plus 28/167 units
of time for the whole distance. In the second race, Percy still takes
1 and 28/167 (or 1.16766) units of time to finish. Tommy finishes
in 1 and 32/195 (or 1.16410) units of time. So Tommy still finishes
first and wins the second race also.
This MindBender was modified from a puzzle in Victor Serebriakoff's
book, "The Mammoth Book of Mindbending Puzzles."
___________________________
Answer to Mini-MindBender for Kids
Candy
Use Algebra to help solve this puzzle. Let J be the price of one
jelly bean and D be the price of one fruit drop. Then we have:
6J + 5D = 85
5J + 6D = 80
Multiplying the first equation by 6 and the second by 5 gives us:
36J + 30D = 510
25J + 30D = 400
Subtracting this second equation from this first equation gives:
11J = 110 or J = 10
Substituting back into the very first equation gives us:
6*10 + 5D = 85 or 5D = 25 or D = 5
So jelly beans are 10 cents each and fruit drops are 5 cents each.
This MindBender was modified from a puzzle in Dr. Abbie F. Salny's
"The Mensa 365 Brain Puzzlers Calendar" for 2001.
May 14, 2001
MindBender
Hiking
A hiker climbs a hill. She averages two miles per hour going uphill
and six miles per hour going downhill. Going uphill and down, and
assuming no time for resting, what will be her average speed for
the entire hike?
___________________________
Mini-MindBender for Kids
Palindrome
A palindrome is a word or sentence that reads the same backward
and forward. Fill in the following blanks to make a palindrome.
For Mother's Day the children called the florist to place a
_ _ _ _ _ _ _ _ _ _ _ _ _
___________________________
...Answer to MindBender
Hiking
3 miles per hour. While at first it may seem that you need to know how
long the hike was in either miles or hours, neither is required. She
obviously spends three times as long going uphill as downhill. Let her
time going downhill be T hours and her time going uphill be 3T hours.
The her total trip is 2*3T + 6*T miles or 12T miles and it takes 4T
hours total for the entire hike. Therefore, her average speed is
12T/4T or 3 miles per hour.
This MindBender was modified from a puzzle in C. R. Wylie Jr.'s book,
"101 Puzzles in Thought & Logic."
___________________________
Answer to Mini-MindBender for Kids
Palindrome
R E D R O S E S O R D E R
This MindBender was modified from a puzzle in Dr. Abbie F. Salny's
"The Mensa 365 Brain Puzzlers Calendar" for 2001.
May 21, 2001
MindBender
In Balance
Timothy owns a good balance, but no weights. He decides to make his
own weights by cutting a 121-gram bar of metal into a number of
pieces (assume no cutting loss). What is the least number of pieces
(weights) necessary so Timothy can weigh any item that weighs any
whole number of grams from 1 to 121?
___________________________
Mini-MindBender for Kids
How Old
How old are you in days? How old are you in seconds? Have you passed
any significant birthdays (like 1,000 or 1,000,000)? You might be
surprised at how "old" you are in days or seconds.
___________________________
...Answer to MindBender
In Balance
Only 5 pieces are needed. Timothy divides the bar into parts of 1, 3,
9, 27, and 81 grams. By placing the object to be weighed on one side
of the balance and selecting the right weights (of the above 5) on
the two sides of the balance, Timothy can weigh any object up to 121
grams. For example, to weigh an object of 20 grams, put the object
and the 1 gram and the 9 gram weights on one side of the balance, and
the 3 gram and the 27 gram weights on the other side.
This MindBender was modified from a puzzle in Pierre Berloquin's book,
"100 Numerical Games."
___________________________
Answer to Mini-MindBender for Kids
How Old
Multiply your age in whole years by 365. Add in 1 for each of those
years that was a leap year. Add in the number of days from your
last birthday until now. This gives you the number of days old that
you are. Since there are 24*60*60 or 86,400 seconds in each day (24
hours per day, 60 minutes per hour, 60 seconds per minute),
multiply that number of days by 86,400 to get your age in seconds.
Suppose that you were born on March 10, 1991. You are now 10 years
old. There have been 3 leap years since then (1992, 1996, and 2000).
Since March 10, there have been 73 (21 days after the 10th in March,
30 days in April, and 22 days so far in May). So in days, you are
now 10*365 + 3 + 73 = 3726 days old. You then are 321,926,400 seconds
old (3726*86400). That's almost 322 million seconds old!
The MindBender moderator is the source for this Mini-MindBender.
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If you have any riddles or MindBenders to add please
e-mail me or
e-mail Mike Avery
PaintSaint helped make this page. check out his
Riddles page.
